Question

Solve the following simultaneous linear equations by elimination method:-
1) 41x+53y=135
53x+41y=147

Answer 1

Answer:

Step-by-step explanation:

41x+53y=135------------ (1)

53x+41y=147-------------(2)

by elimination method,

multiply 41 in eq.(1) and multiply 53 in eq.(2),

(41x+53y=135)×41

(53x+41y=147)×53

1681x+2173y=5535

2809x+2173y=7791

- - -

__________________(by subtracting)

-1128x = -2256. (2173y-2173y cancelled)

x = -2256/-1128(- and - is cancelled

x = 2

put the value of x in eq. (2),

53x+41y=147

53×2+41y=147

106+41y=147

41y=147-106

41y=41

y=41/41

y=1

so the value of x=2

y=1

Ans.

I hope this is helpful to you.