Question

Solve the following simultaneous linear equations in two variables: i. q²x-p²y = 0, px +qy=p³ + q³

Answer 1

Given is q^2 x - p^2 y = 0
=> x = p^2 y / q^2

Now put this value of x in 2nd equation, we get
p ( p^2 y / q^2)x + qy = p^3 + q^3
p^3 xy/ q^2 + qy = p^3 + q^3

Answer 2

$\bold{Given \: is \: q²x-p²y = 0}$

$\bold{ \implies \: x = \frac{ {p}^{2}y}{ {q}^{2} } }$

Now put this value of x in second equation, we get

$\bold{p( \frac{ {p}^{2}y }{ {q}^{2} } )x + qy = {p}^{3} + {q}^{3}}$

$\bold{\frac{{p}^{3} xy}{ {q}^{2} + qy } = {p}^{3} + {q}^{3}}$