Question

solve the following simultaneous question 1/3x + 2y=+18 ; 1/3 x + 6y = 30
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Answer 1

Answer: x=36, y=3

Step-by-step explanation:

1/3x+2y=18

1/3x+6y=30

Subtract 2nd from 1st:

4y=12

y=3

Find x:

1/3x+2×3=18

1/3x=12

x=36

Verify:

1/3×36+2×3=12+6=18

1/3×36+6×3=12+18=30

Answer 2

Answer:

x=36, y=3

Step-by-step explanation:

⅓x+2y=18--eq1

⅓x+6y=30--eq2

Add eq1 and eq2, we get

4y=12

y=12/4

y=3

Substitute y=3 in eq1

⅓x+2y=18

⅓x+2(3)=18

⅓x+6=18

⅓x=18-6

⅓x=12

x=12×3

x=36