Question

solve the following simultaneous system of equations : 4/√x+3/√y=7/2 , 8/√x+6/√y = 1​

Answer 1

Answer:

+

3y

1

=2

3x

1

+

2y

1

=

6

13

Lets assume

x

1

=p and

y

1

=q, both equations will become

2

p

+

3

q

=2

⇒3p+2q=12 ... (A)

3

p

+

2

q

=

6

13

⇒2p+3q=13 ...(B)

Multiply (A) by 3 and (B) by 2, we get

9p+6q=36

4p+6q=26

Subtracting these both, we get

5p=10

⇒p=2

⇒x=

p

1

=

2

1

∴q=

6

26−8

=3

⇒y=

q

1

=

3

1