Solve the following simultanes equation. Plzzzzzzz.
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3a+5b=26
3a=26-5b
a=26-5b/3
Put this value in place of a in the other equation.
26-5b/3 -5b=22
26-5b-15b/3=66
26-20b=66
-20b=40
b=-2
3a=26-5b
a=26-5b/3
Put this value in place of a in the other equation.
26-5b/3 -5b=22
26-5b-15b/3=66
26-20b=66
-20b=40
b=-2
Alinashaikh49:
Can I ask again one equation............
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