solve the following simultaneus equations 1)5x-3y=8;3x+y=2
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5x-3y=8 .................... (i)
3x+y=2 .................... (ii)
From second equation :-
x = 2-y / 3.
Substitute the x value in the first equation :-
5(2-y/3)-3y=8
10 - 5y / 3 - 3y = 8
10 - 5y/3 = 8 + 3y
Now cross multiply
10 - 5y = 3(8+3y)
10 - 5y = 24 + 9y
-14y = 34
y = -34 / 14.
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