Question

Solve the following step by step​

Answer 1

Answer:

1

Step-by-step explanation:

2sec(θ)/(1+tan²θ)

2sec(θ)/sec²θ.....as sec²θ-tan²θ=1

2/sec(θ)

2cosθ

and cosθ=1/2...given

2cosθ=1

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Answer 2

$Cos \theta = \frac{1}{2} = \frac{base}{hypotenuse}$

so,

$2^2 = 1^2 + x^2$

$\sqrt{3} = perpendicular$

now putting them all accordingly to

$\frac{2 sec\theta}{1 + tan^{2} \theta}$

$\frac{4}{1 + \sqrt{3}^{2}$

$= 1$