Math, asked by siddhusingh8858, 1 month ago

Solve the following sums: (a) Find the value of 34²-21². (b) If a=5-2√5, then find a². ​

Answers

Answered by rutikjadhav4567
2

Answer:

Answer:715

Answer:715Step-by-step explanation:

Answer:715Step-by-step explanation:34^2 - 21^2 = 1156-441= 715

Answer:715Step-by-step explanation:34^2 - 21^2 = 1156-441= 715a^2 = 0.527

Answered by halamadrid
3

The correct answers area)The value of 34²-21² is 715 and b) The value of a² is 45 - 20√5.

Given:

a) The expression 34²-21²

b) a = 5-2√5

To Find:

a) The value of 34²-21².

b) The value of a².

Solution:

a) We have been asked to find the value of  34²-21².

To solve this problem, we will use the concept

a² - b² = (a - b)(a + b)

By comparing with the given question:

a = 34 and b = 21

∴ 34²-21² = (34 - 21)(34 + 21) = 13 x 55 = 715

∴ The value of 34²-21² is 715.

b) We have been asked to find the value of  a², if a = 5-2√5

⇒ a² = (5-2√5)²  .....................(I)

To solve this problem, we will use the concept

(x - y)² = x² - 2xy + y²

By comparing (I) to the above equation, we have

x = 5 and y = 2√5

∴ a² = (5-2√5)² = 5² - 2(5)(2√5) + (2√5)² = 25 - 20√5 + 20

⇒ a² = 45 - 20√5.

∴ The value of a² is 45 - 20√5.

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