Math, asked by simrankaur86, 1 year ago

solve the following system of eqn.
8v -3u = 5uv
6v - 5u = -2uv ; u is not equal to 0,
v is not equal to 0
please solve it as soon as possible.
I am waiting

Answers

Answered by vinayakbala32
1

Answer:

so

(8v-3u)/5 = (6v-5u)/2

16v - 6u = 30v - 25u

19u=14v

v=1.35u

substitute this in  equation to get value of u.

Answered by Maxcaulfield
1

Easy,

8v - 3u = 5uv × 5

6v - 5u = -2uv × 3

40v - 15u = 25uv

18v - 15u = -6uv

(-)_(+)_____(+)__

22v - 0u = 31uv

________________

22v = 31uv

So, v is canceled from both side

31u = 22

u = 22/31

6v - 5u = -2uv

6v -5×22/31 = -2 × 22/31 × v

6v - 110 = -44/31v

6v + 44/31v = 110

Taking LCM,

186/31v + 44/31v = 110

230/31v = 110

v = 110×31/230

v = =14.8260869565

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