solve the following system of equation 2x + Y - 3 is equal to zero 2 x minus 3 Y - 7 is equal to zero
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Answer:
2x+Y-3=0 (1st equation)
2x-3Y-7=0 (2nd equation)
On subtracting 1st equation from 2nd equation we get,
2x+Y-3-(2x-3Y-7)=0
2x+Y-3-2x+3Y+7=0
4Y+4=0
4Y= -4
Y= (-1)
On substituting value of Y in 1st equation we get,
2x+Y-3=0
2x+(-1)-3=0
2x-1-3=0
2x-4=0
2x=4
x=2
Hence (2,-1) is the solution for these two equations..
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represent 6,-4 ,0 give m3 answer
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