Math, asked by bhattijat2912, 8 months ago

Solve the following system of equation 3x-2y+7z=5
7x+y+9z=6
3x+3y-7z=0

Answers

Answered by CharmingPrince
0

Answer :

Solution 1

= 3x-2y+7z=5

= 3x = 5 + 2y - 7z

  • Multiplying both sides of the equation with 3

= x = \dfrac{5}{3} + \dfrac{2}{3}y - \dfrac{7}{3}z

Solution 2

= 7x+y+9z=6

= 7x = 6 - y - 9z

  • Multiplying both sides of the equation with 7

= x = \dfrac{6}{7} - \dfrac{1}{7}y - \dfrac{9}{7}z

Solution 3

= 3x+3y-7z=0

= 3x = -3x + 7z

  • Multiplying both sides of the equation with 3.

= x = - y +\dfrac{7}{3} z

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