Solve the following system of equation 3x-7y+10=0
Y-2x-3=0
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Given,
3x - 7y + 10 = 0
y - 2x - 3 = 0
So,
3x - 7y + 10 = 0 ……….... (1)
y - 2x - 3 = 0 ……….... (2)
From (2),
y - 2x - 3 = 0
y = 2x + 3 …………. (3)
Putting value of y in (1),
3x - 7(2x + 3) + 10 = 0
3x - 14x - 21 + 10 = 0
-11x = 11
x = -1
Now,
Substituting value of x in (3),
y = 2x + 3
y = 2(-1) + 3
y = 1
Therefore,
x = -1 and y = 1
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