solve the following system of equation by cross multiplication method 11x+15y+23=0,7x-2y-20=0
khushi0501:
is the value of either x or y given?
Answers
Answered by
3
11x+5y+23=0
7x-2y-20=0
therefore,11x+5y+23=7x-2y-20
11x-7x+5y+2y=-20-23(by transposing)
4x+7y= (-43)
7x-2y-20=0
therefore,11x+5y+23=7x-2y-20
11x-7x+5y+2y=-20-23(by transposing)
4x+7y= (-43)
Similar questions