Question

solve the following system of equation by elimination method 5x + 3y=70 ; 3x-7y=60.​

Answer 1

Answer:

$\huge\underline{ \underline{ \red{your \: \: answer}}}$$\sf\red\{substitution .method}}$

Step-by-step explanation:

$\sf\red{5x + 3y = 70 - - - - (1)} \\ \sf\red{3x - 7y = 60 - - - - (2)} \\ \sf\red{ = > x = \frac{60 + 7y}{3} - - - (3)} \\ \sf\pink{value \: of \: x \: put \: in \: (1)} \\ \sf\red{ = >5 \times \frac{60 + 7y}{3} + 3y = 70 } \\ \sf\red{ = > \frac{300 + 35y}{3} + 3y = 70 } \\ \sf\red{ = > \frac{300 + 35y + 9y}{3} = 70 } \\ \sf\red{ = > 300 + 44y = 210} \\ \sf\red{ = > 44y = - 90} \\ \sf\red{ = > y = \frac{ - 45}{22} } \\ \sf\purple{value \: of \: y \: put \: in \: (3) } \\ \sf\red{x = \frac{60 - \frac{315}{22} }{3} } \\ \sf\red{=>x = \frac{ \frac{1320 - 315}{22} }{3} } \\ \sf\red{ => x = \frac{335}{22} }$

$\large\boxed{ \fcolorbox{red}{yellow}{hope \: it \: help \: you}}$

Answer 2

Answer:

answer is 2

I hope it help you