Question

solve the following system of equation by substituting method .3.3x+2y=11 ,2x+3y=4​

Answer 1

Step-by-step explanation:

solution:-

3x+2y=11 .......(i)eq

2x+3y=4 ......(ii)eq

by using substitution method,we get

take eq(i) find the value of x

3x+2y=11 ..........(i)eq

3x=11-2y

$x = \frac{11 - 2y}{3}$

now put the value of x on (ii)eq

$2( \frac{11 - 2y}{3} ) + 3y = 4$

$\frac{22 - 4y}{3} + 3y = 4$

now take lcm

$\frac{22 - 4y + 9y}{3} = 4$

now 3 is multiply on RHS

22-4y+9y=12

5y=12-22

5y= -10

y= -2

now put the value of y in x ,we get

$x = \frac{11 - 2 \times - 2}{ 3}$

$x = \frac{11 + 4}{3}$

$x = \frac{15}{3}$

x=5

the value of x=5 and y= -2