Question

solve the following system of equation for x and y by cross multiplication. 11x+5y-7=0 and 6x-3y-21=0​

Answer 1

Answer:

The values of x and y are 2 and -3 respectively

Step-by-step explanation:

We need to solve these equations simultaneously.

Let's first rewrite the equations as follows:

11x + 5y = 7 .................i)

6x - 3y = 21 ...................ii)

Lets eliminate y.

So, we multiply equation i by 3 and equation ii by 5 to get:

33x + 15y = 21..................iii)

30x - 15y = 105 .................iv)

Let's add the two equations to get:

63x = 126

x = 126/63

x = 2

Let's substitute this value of x in equation i to get y.

We have:

11 × 2 + 5y = 7

22 + 5y = 7

5y = 7 - 22

5y = -15

y = -15/5

y = -3

The values of x and y are 2 and -3 respectively.