solve the following system of equation graphiclly:x+3y=6
2x-3y=12
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Solve the following system of equation graphically:
x+3y=6 and 2x-3y=12
~ Firstly let us consider
- x + 3y = 6...Equation 1
- 2x - 3y = 12...Equation 2
~ Put x as 0 in equation 1.
→ x + 3y = 6
→ 0 + 3y = 6
→ 3y = 6
→ y = 6/3
→ y = 2
- Henceforth, coordinates (0,2)
~ Now put y as 0 in equation 1.
→ x + 3y = 6
→ x + 3(0) = 6
→ x + 0 = 6
→ x = 6
- Henceforth, coordinates (6,0)
~ Now put x as 0 in equation 2.
→ 2x - 3y = 12
→ 2(0) - 3y = 12
→ 0 - 3y = 12
→ -3y = 12
→ y = -12/3
→ y = -4
- Henceforth, coordinates (0,-4)
~ Now put y as 0 in equation 2.
→ 2x - 3y = 12
→ 2x - 3(0) = 12
→ 2x - 0 = 12
→ 2x = 12
→ x = 12/2
→ x = 6
- Henceforth, coordinates (6,0)
They intersect at (6,0)
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