solve the following system of equation x+2y=3/2 2×+y=3/2
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x+2y=3/2.......(1)
2x+y=3/2......(2)
Adding equations (1) and (2) we get
3x+3y=3
therefore, x+y=1..... dividing throughout by3
....... (3)
now subtracting equation (1) from (2) we get
x-y=0
x=y........ (4)
Substituting value of x in equation (3) we get
y +y=1
2y=
y=1/2.
substituting the value of y in equation (3)
x+1/2=1
x=1/2
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