solve the following system of equations.
11x - 8y = 27
3x + 5y = -7
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From (1), we get
11x = 8y + 27, or
x = 8y + 27/11
Putting this value of x in (2), we have
3(8y + 27/11) + 5y = -7
=> 24y + 81 +55y = -77
79y = -77 -81 = -158
=> y = -158/79
= -2
substituting the value of y in (3), we have
x = 8 × (-2) + 27/11
= -16 + 27/11
= 11/11
= 1
glad help you
it helps you
thank you☺
11x = 8y + 27, or
x = 8y + 27/11
Putting this value of x in (2), we have
3(8y + 27/11) + 5y = -7
=> 24y + 81 +55y = -77
79y = -77 -81 = -158
=> y = -158/79
= -2
substituting the value of y in (3), we have
x = 8 × (-2) + 27/11
= -16 + 27/11
= 11/11
= 1
glad help you
it helps you
thank you☺
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