Math, asked by roopasreejith, 5 months ago

. Solve the following system of equations :
21/x + 47/y= 110
27/x +21/y = 162
x, y ≠ 0​

Answers

Answered by abhishekapurva727
0

Answer:

Divide 10 into two parts in such a manner that if we add to each part its square root and form the product of the resulting sums, we obtain an integar.Giveyears = 28 years

breadth

Exercise 2.2

1.

2.

Two-thirds of a number is 5 more than half of it. What is the number?

Fifteen years from now Ravi's age will be four times his present age.

3. Ram has 3 times as many 2 coins as he has 5 coins. If he has in a

of 2 does he have?

4. The sum of three consecutive numbers is 156. Find the number w

numbers.

5. Divide 63 into two parts such that one part is

2

of the other.

Find a number whose fifth part increased by 30 is equal to itnumber is divided into two parts such that one part is 5 more than the other.If the parts are in the ratio 4:3,find the number and the two parts?

Given below are the ages of 30 students of Class-VIII in a school.

13

14

14

12.

15

15

14

13

13

14

14

13

14

14

12

14

13

12

13

14

14

13

12

13

12

13

14

15

14

an

Answered by nvnitin160778
0

Answer:

21u+47=100

21u=100-47

21u=63

u=63/21

u=3

now,

x=1/u=1/3

y = 1/v =1/1=1

so,x=1/3,y=1

Step-by-step explanation:

पहले सारी फोटो है उसके बाद इस आंसर को लिखना जो मैंने आंसर लिख कर भेजा है

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