Question

Solve the following system of equations:
21/x+47/y=110
47/x+21/y=162, x,y is not equal to 0

Answer 1

Step-by-step explanation:

we are given the two equation,

so,let (1/x) be (a) and (1/y) be (b)

21a +47b = 110 .........(1)

47a + 21b = 162 ........(2)

now, a short trick to find x and y

add both the equation,

by adding the equation ,we get ,

a+ b = 4 ........(3)

now, by subtracting the equation,we get ,

a-b = 2 ........(4)

now, solve the equation 3 and 4 by any method,

by solving ,we get,

a= 3 and b= 1

comparing the equation,

(1/x) = 3 , (1/y) = 1

x = 1/3 y= 1

hope u like it...

the trick I had shown above is the easy way to solve this type of sum....