Question

solve the following system of equations
21/x+47/y=110 and 27/x+21/y=162,x,y≠0​

Answer 1

Answer:

(2209x+987y)−(441x+987y)=7614−2310

1768x=5304

⇒x=

1768

5304

=3

Substituting the value of x in equation (1), we have

21×3+47y=110

⇒47y=110−63

⇒y=

47

47

=1

Therefore,

x=3 and y=1.