Question

Solve the following system of equations 2x+7y=4 -4x-3y=14

Answer 1

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Hey Mate!!

2x + 7y = 4

=> 2x = 4 - 7y _________(1)

-4x - 3y = 14

=> -2(2x) - 3y = 14

=> -2(4 - 7y) - 3y = 14 ________(from (1))

=> -8 + 14y - 3y = 14

=> -8 + 11y = 14

=> 11y = 14 + 8

=> 11y = 22

=> y = 22 ÷ 11

=> y = 2 ________(2)

By substituting (2) in (1),

=> 2x = 4 - 7y

=> 2x = 4 - 7(2)

=> 2x = 4 - 14

=> 2x = -10

=> x = (-10) ÷ 2

=> x = (-5)

Answer 2

Answer:

=> The value of x = -5, and y = 2.

Step-by-step explanation:

Given that:-

$2x + 7y = 4$

=> $2x = 4 - 7y$      $...(i)$

$-4x - 3y = 14$

=> $-2 (2x) - 3y = 14$    $...(ii)$

From equation ( i )

=> $-2(4 - 7y) - 3y = 14$

By further calculation, we get

=> $-8 + 14y - 3y = 14$

=> $-8 + 11y = 14$

=> $11y = 14 + 8$

=> $11y = 22$

Divide by  on both the sides, we get

=> y = 2

So, the value of y is 2.

Now, put the value of y as 2 in the equation ( 1 ):

=> $2x = 4 - 7y$

=> $2x = 4 - 7(2)$

=> $2x = 4 - 14$

=> $2x = -10$

Divide by  on both the sides, we get

=> $x =-5$

So, the value of x is -5.