solve the following system of equations by cross multiplication method
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(x/a) + (y/b) = a + b
Multiply by (1/a) both sides, we get
(x/a²) + (y/ab) = 1 + (b/a) ............ (1)
(x/a²) + (y/b²) = 2 .................. (2) (given)
Subtract (2) from (1), we get
(x/a²) + (y/ab) - x/a² - y/b² = 1 + (b/a)
(x/a²) + (y/b²) - (x/a²) - (y/ab)= 2 - 1 - b/a
y/b² - y/ab = 1 - b/a
(yab - yb)/ab³ = 1 - b/a
(ya - yb)/ab² = 1 - b/a
y (a-b)/ab² = (a - b)/a
y = [b²(a-b)] / ( a-b)
y = b²
Now put y = b² in equation x/a² + y/b² = 2
x/a² + b²/b² = 2
x/a² = 2- 1 = 1
x = a²
= bx + ay = (a+b)ab
= xb + ya = a²b + ab²
= a²b + ab² - xb - ya
chakitsharma7:
your answer is correct
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