Question

Solve the following system of equations by eliminating 3x+4y-7=0 and 2x-y+2=0

Answer 1

Step-by-step explanation:

3x+4y-7=0 =>3x+4y=7...(1)

2x-y+2=0 => 2x-y = -2...(2)

Multiply (2) by 4 and add (1)

3x+4y+4(2x-y)=7+4(-2) =>3x+8x = -1=>11x= -1 => x = -1/11 and Substitute x = -1/11 in equation(1) =>3(-1/11)+4y=7 =>4y= 7+ 3/11 =>y= (77+3/11)/4 =>y=20/11 Hence x = -1/11 and y=20/11.Hope it helps you.