Question

solve the following system of equations by elimination method 5x-2y=1 ; x+3y=7
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Answer 1

Answer:

x=1 and y=2

Step-by-step explanation:

Let's solve your system by substitution.

5x−2y=1;x+3y=7

Rewrite equations:

x+3y=7;5x−2y=1

Step: Solvex+3y=7 for x:

x+3y=7

x+3y+−3y=7+−3y(Add -3y to both sides)

x=−3y+7

Step: Substitute−3y+7for x in5x−2y=1:

5x−2y=1

5(−3y+7)−2y=1

−17y+35=1(Simplify both sides of the equation)

−17y+35+−35=1+−35(Add -35 to both sides)

−17y=−34

−17y/−17=−34/−17(Divide both sides by -17)

y=2

Step: Substitute2for y in x=−3y+7:

x=−3y+7

x=(−3)(2)+7

x=1(Simplify both sides of the equation)

Answer:

x=1 and y=2

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Answer 2

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