Math, asked by nikhilbachhav989, 4 months ago

solve the following system of equations by gauass jordan method 3x-y+2z=12,X+2y+3z=11,2x-2y-z=2​

Answers

Answered by Mansimehra23109
2

Answer:

3x-y+2z=12_____(1)

x+2y+3z= 11______(2)

2x-2y-z=2______(3)

multiply both sides of 2 by 2

2x+4y +6z =22____(4)

subtracting 3 from 4

6y +7z = 20____(5)

multiply both sides of 2 by 3

3x +6y+9z = 33____(6)

subtracting 1 from 6

7y +7z = 21_____(7)

subtracting 5 from 7

y = 1

put the value of Y in equation 7

z=2

putting the value of Y and Z in equation 3

x= 3

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