Solve the following system of equations by substitution method.
2x – y = 2 and x + 3y = 15
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2x - y = 2
y = 2x - 2.(1)
X + 3y = 15...(2)
Substituting the value of y from (1) in (2), we get,
X + 6x - 6 = 15
7x = 21
X = 3
From (1),
y = 2 x 3 - 2 = 4
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