Question

Solve the following system of equations by substitution method :
2x-y=-1
2x+3y=11
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Answer 1

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Answer 2

Hey here is your answer..


2x - y =- 1

2x= - 1+ y

X= - 1 + y /2

Now putting the value of x in equation 2

2 (-1 + y /2) + 3y = 11
- 2 + 2 y/2 + 3y = 11

- 2 + y + 3y = 11

- 2 + 4y = 11
4y = 11 +2

Y= 13/4

Now we have to find the value of y.

X=- 1 + 13/4 × 2
X - 1 + 26 /4
X= - 4 + 26 /4
X= 22/4


So x = 22/4

Y = 13/4.


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