Question

Solve the following system of equations by substitution method: 5x+2y=8, 3x-5y=11

Answer 1

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Answer 2

Solution :

Given simultaneous equations

5x + 2y = 8 -----( 1 )

3x - 5y = 11

=> 3x = 11 + 5y

=> x = ( 11 + 5y )/3 -----( 2 )

Substitute ( 2 ) in equation ( 1 ) , we get

5[( 11 + 5y )/3 ] + 2y = 8

=> ( 55 + 25y + 6y )/3 = 8

=> ( 31y + 55 ) = 24

=> 31y = 24 - 55

=> 31y = -31

=> y = ( -31 )/31

=> y = -1

Now ,

put y = -1 in equation ( 2 ), we get

x = [ 11 + 5( -1 )]/3

= ( 11 - 5 )/3

= 6/3

= 2

Therefore ,

x = 2 , y = -1

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