Solve the following system of equations by using the method of substitution.
3x – 5y = –1; x – y = –1
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add on both sides
5 (x-y)=-1+2x
5 (-1)=-1+2x
-5+1=2x
-4=2x
x=-2
sub x=-2 in 3x-5y=-1
3 (-2)-5y=-1
-6-5y=-1
-5y=5
y=-1
5 (x-y)=-1+2x
5 (-1)=-1+2x
-5+1=2x
-4=2x
x=-2
sub x=-2 in 3x-5y=-1
3 (-2)-5y=-1
-6-5y=-1
-5y=5
y=-1
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