Question

Solve the following system of equations graphically.

2x− y = 4

3y− x= 3

Shade the region bounded by the lines and x- axis. Also, find the area bounded by the y axix​

Answer 1

Question :-

Solve the following system of equations graphically.

2x− y = 4

3y− x= 3

Shade the region bounded by the lines and x- axis. Also, find the area bounded by the y axis.

Solution :-

When we solve the graph question of equation, first solve the equation and take one variable in a side. And by substitution method make 3 co ordinates of x and y. Then draw the graph.

In this question we have to also shade the bounded region in the graph.

1] 2x - y = 4

→ 2x - 4 = y

y = 2x - 4

Put x = 0

y = 2(0) - 4

y = -4

(x,y) = (0,-4)

Put x = 1

y = 2(1) - 4

y = 2 - 4

y = -2

(x,y) = (1,-2)

Put x = 2

y = 2(2) - 4

y = 4 - 4

y = 0

(x,y) = (2,0)

Co ordinate Table :-

$\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{c|c|c} \bf x,y & \bf x & \bf y \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 0, - 4 & \sf 0 & \sf - 4 \\ \\ \sf 1, - 2 & \sf 1 & \sf - 2\\ \\ \sf 2,0 & \sf 2&\sf 0 \end{array}} \\ \end{gathered}\end{gathered}\end{gathered}$

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2] 3y− x= 3

→ y - x = 3/3

→ y - x = 1

y = 1 + x

Put x = 0

→ y = 1 + 0

→ y = 1

(x,y) = (0,1)

Put x = 1

→ y = 1 + 1

→ y = 2

(x,y) = (1,2)

Put x = 2

→ y = 1 + 2

→ y = 3

(x,y) = (2,3)

Co ordinate Table :-

$\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{c|c|c} \bf x,y & \bf x & \bf y \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 0,1 & \sf 0 & \sf 1 \\ \\ \sf 1,2 & \sf 1 & \sf 2\\ \\ \sf 2,3 & \sf 2&\sf 3 \end{array}} \\ \end{gathered}\end{gathered}\end{gathered}$

[Note : Graph is attached to the answer.

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Answer 2

Answer:

here is ur answer

Step-by-step explanation:

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