solve the following system of equations using Cramer's rule.
3x+4y=11;5x+3y=11
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Required Equations :
3x + 4y = 11
5x + 3y = 11
Let A be the constant determinant.
A = 3(3)-4(5) = 9 - 20 = -11 .
Let B be the X determinant.
B = 11(3)-4(11) = -11
Let C be the determinant.
C = 3(11)-11(5) = -22 .
Now,
X = X determinant / constant determinant = -11 / -11 = 1 .
Y = Y determinant / Constant determinant
= -22/-11 = 2 .
Therefore, ( 1 , 2 ) is the solution of system of equations ( 3x + 4y =11 , 5x + 3y = 11 )
3x + 4y = 11
5x + 3y = 11
Let A be the constant determinant.
A = 3(3)-4(5) = 9 - 20 = -11 .
Let B be the X determinant.
B = 11(3)-4(11) = -11
Let C be the determinant.
C = 3(11)-11(5) = -22 .
Now,
X = X determinant / constant determinant = -11 / -11 = 1 .
Y = Y determinant / Constant determinant
= -22/-11 = 2 .
Therefore, ( 1 , 2 ) is the solution of system of equations ( 3x + 4y =11 , 5x + 3y = 11 )
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