Question

Solve the following system of equations x/2 + 2y/3 = -1 and x - y/3 =3

Answer 1

Answer:

x = 2

y = -3

Step-by-step explanation:

$\frac{x}{2} +\frac{2y}{3} = -1\\\\\frac{3x+4y}{6}=-1\\ \\3x+4y=-6 ----------(1)$

$x-\frac{y}{3}=3\\ \\3x-y=9 ----------(2)$

subtracting eq. (1) and (2), we get:

$(3x+4y) - (3x-y)=-6-9\\3x+4y-3x+y=-15\\5y=-15\\y=-3$

using eq. 2 :

$3x-y=9\\3x-(-3)=9\\3x+3=9\\3x=6\\x=2$

hence, x = 2, y = -3