Question

Solve the following system of equations x - 2 y = 0 ; 3x + 4y = 20

Answer 1

Given equations

$x - 2y = 0\\3x+4y = 20$

Now,

$x - 2y = 0\\\implies x = 2y$

Substituting  x in the second equation, we get,

$\implies 3(2y)+4y = 20\\\implies 6y + 4y = 20\\\implies 10y=20$

$\implies y = \dfrac{20}{10}$

$\implies y = 2$

$\implies x = 4$

$\boxed{\boxed{\bold{Therefore, \ the \ values \ of \ x \ and \ y \ are \ 4 \ and \ 2}}}}$