Question

solve the following system of equations
x+2y=0​

Answer 1

x−2y=0

or, x=2y(1).

And

3x+4y=20(2).

Now, using values of x in (2) we get,

10y=20

or, y=2.

Then x=4.

So, solutions is x=4,y=2.

Answer 2

x−2y=0

or, x=2y(1).

And

3x+4y=20(2).

Now, using values of x in (2) we get,

10y=20

or, y=2.

Then x=4.

So, solutions is x=4,y=2.

Answer 3

x−2y=0

or, x=2y(1).

And

3x+4y=20(2).

Now, using values of x in (2) we get,

10y=20

or, y=2.

Then x=4.

So, solutions is x=4,y=2.

Answer 4

x−2y=0

or, x=2y(1).

And

3x+4y=20(2).

Now, using values of x in (2) we get,

10y=20

or, y=2.

Then x=4.

So, solutions is x=4,y=2.

Answer 5

x−2y=0

or, x=2y(1).

And

3x+4y=20(2).

Now, using values of x in (2) we get,

10y=20

or, y=2.

Then x=4.

So, solutions is x=4,y=2.

Answer 6

x−2y=0

or, x=2y(1).

And

3x+4y=20(2).

Now, using values of x in (2) we get,

10y=20

or, y=2.

Then x=4.

So, solutions is x=4,y=2.

Answer 7

x−2y=0

or, x=2y(1).

And

3x+4y=20(2).

Now, using values of x in (2) we get,

10y=20

or, y=2.

Then x=4.

So, solutions is x=4,y=2.

Answer 8

x−2y=0

or, x=2y(1).

And

3x+4y=20(2).

Now, using values of x in (2) we get,

10y=20

or, y=2.

Then x=4.

So, solutions is x=4,y=2.

Answer 9

x−2y=0

or, x=2y(1).

And

3x+4y=20(2).

Now, using values of x in (2) we get,

10y=20

or, y=2.

Then x=4.

So, solutions is x=4,y=2.