Question

Solve the following system of equations x+8y=19 and 2x+1y=28, by substitution method and verify it.​

Answer 1

Answer:

the answer is x = 3 and y = 2

Answer 2

The solution of equation is $\bf \: x = 3 \: and \: y = 2$

*Correct question

Given:

• A pair of linear equations.
• $x + 8y = 19$
• $2x + 11y = 28$

To find:

• Find the solution of linear equations using the substitution method.
• Verify the answer.

Solution:

Concept/formula to be used:

• Put the value of one variable from one equation into another equation.
• Varify the equation by putting the solution into one equation.

Step 1:

Substitute the value x from eq1.

Let

$x + 8y = 19 ...eq1$

So,

$\bf x = 19 - 8y$

Put the value of x into another equation.

$2(19 - 8y) + 11y = 28$

$38 - 16y + 11y = 28$

$- 5y = 28 - 38$

$- 5y = - 10$

$\bf \: y = 2$

Put the value of y in eq 1.

$x + 8(2) = 19$

$x + 16 = 19$

$x = 19 - 16$

$\bf \: x = 3$

Thus,

The values of x and y are 3 and 2 respectively.

Step 2:

Verify the solution.

Put the values of x and y in eq 1.

$x + 8y = 19$

$3 + 8(2) = 19$

$3 + 16 = 19$

$\bf 19 = 19$

LHS= RHS

Thus,

The solution is verified.

Learn more:

1) 3x+2y=8 and 2x-y=3 solve pair of linear equation by elimination method

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2) Solve each of the following pairs of equations by the elimination method.1. 8x+ 5y = 9 3x+2y = 4

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