Question

solve the following system of equations X upon A plus Y upon B is equals to a + b ;X upon A square + Y upon B square is equals to 2

Please guys help me and get 30 pts
But don't post irrelevant answers​

Answer 1

Given : $\frac{X}{A}+\frac{Y}{B}= A+B$

$\frac{X}{A^2}+\frac{Y}{B^2}=2$

explanation:

$\frac{X}{A}+\frac{Y}{B}= A+B..(1)\\\\\frac{X}{A^2}+\frac{Y}{B^2}=2..(2)\\\\\text{multiply 1 by 2}\\\\\frac{X}{AB}+\frac{Y}{B^2}=\frac{A+B}{B}..(3)\\\\\text{using elimination subtract 3 by 2 }\\\\we get\\\\X=A^2\\\\\text{put the value of X in eq. 2}\\\\\frac{X}{A^2}+\frac{Y}{B^2}=2\\\\\frac{A^2}{A^2}+\frac{Y}{B^2}=2\\\\Y= B^2$

Hence , The value of X is A² and Y is B²

#Learn more :

https://brainly.in/question/9858609

Answer 2

Answer:

This answer is right...