Question

Solve the following system of equations x+y-5=0 and 2x-3y-4=0

Answer 1

1) X=2+Y=3

(2+3)=5

5-5=0

2)2X-3Y-4=0

X=0,Y=0

2×X,3×Y

2×0,3×0

0=0

0

Answer 2

Answer:

$x + y = 5........(i)$

$2x - 3y = 4............(ii)$

Multiplying (i) by 2,

$= > 2x + 2y = 10..........(iii)$

Subtracting (ii) from (iii),

$= > (2x + 2y) - (2x - 3y) = ( 10) - (4) \\ = > (2x + 2y - 2x + 3y) = 6 \\ = > 5y = 6 \\ = > y = \frac{6}{5} = 1.2$

Substituting value of y in (i),

$= > x + \frac{6}{5} = 5 \\ = > x = 5 - \frac{6}{5} \\ = > x = \frac{25 - 6}{5} \\ = > x = \frac{19}{5} = 3.8$

Hope this answer helps you ^_^ !