Question

Solve the following system of inequalities graphically
2x + y = 24, x + y < 11, 2x + 5y s 40, x, y 2 0.​

Answer 1

Answer:Inequality (x ≥ 0) represents the region on the right of y-axis and y-axis itself. Inequality y ≥ 0 represents the region above x-axis and x-axis itself. 2x + y ≤ 24, ....(1)  x + y ≥ 11,... (2)  2x + 5y ≤ 40,... (3) We first draw the graph of lines 2x + y ≤ 24, x + y ≥ 11 and 2x + 5y ≤ 40 Now,  2x + y ≤ 24, passes through A(12,0) and B(0,24) Again, x + y ≥ 11, passes through C(11,0) and D(0,11) Further 2x + 5y ≤ 40, passes through E(20,0) and F(0,8) Shaded area PQAC is the solution area. Read more on Sarthaks.com - https://www.sarthaks.com/1037637/solve-the-following-system-of-in-equalities-graphically-2x-y-24-x-y-11-2x-5y-40-x-y-0

Step-by-step explanation: