solve the following system of inequalities graphically, x+y less than or equal to 2, 2x+3y less than or equal to 6, x greater than or equal to 0, y greater than equal to 0.
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Given : x + y ≤ 2
2x + 3y ≤ 6
x ≥ 0
y ≥ 0
To Find : solve the following system of inequalities graphically,
Solution:
x + y ≤ 2
2x + 3y ≤ 6
x ≥ 0
y ≥ 0
x + y ≤ 2
Draw a line x + y = 2
0 , 0 satisfies ≤ 2 inequality
hence region on left of line
2x + 3y ≤ 6
Draw line 2x + 3y = 6
0 , 0 satisfies ≤ 6 inequality
Hence region is on the left
x ≥ 0 , y ≥ 0
so 1st Quadrant only ( above x axis and right of y axis )
Triangle formed by point (0, 0) , ( 0 , 2) and ( 2, 0)
is the solution
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Answer: The answer is D
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