Question

solve the following system of inequalities x square minus 9 is greater than or equal to zero and x square - 6 X + 8 is smaller than or equal to zero​

Answer 1

x {}^{2} - 9 \geqslant 0 \\ x { }^{2} \geqslant 9 \\ x \geqslant 3 \\ \\ x { }^{2} - 6x + 8 \leqslant 0 \\ \\ (x - 4)(x - 2) \leqslant 0 \\ x \leqslant 4 \\ x \leqslant 2 \\ therefore \: 4 \geqslant x \geqslant 3