Question

solve the following system of linear equation
in three variable.
x+y+z=5​

Answer 1

Answer:

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Explanation:

+ y + z = 5  -------(1)

2x − y + z = 9   -------(2)

x − 2y + 3z = 16   -------(3)

Let us add (1) and (2)

Multiply the first equation by 2 and add by (3)

Let 3x + 2z  =  14  ----(4) and 3x + 5z = 26  ---(5)

(4) - (5)  

 3x + 2z  =  14

 3x + 5z  =  26

 (-)   (-)      (-)

 ----------------

     -3z  =  -12  ==> z  =  4

By applying z = 4 in (4), we get

3x + 2(4)  =  14

3x + 8  =  12

3x  =  14 - 8

3x  =  6  ==>  x  =  2

By applying x 2 and z = 4 in (1), we get  

2 + y + 4  =  5

6 + y  =  5  

y  =  5 - 6

y  =  -1

Hence the required solution is x = 2, y = -1 and z = 2.

Answer 2

Answer:x+y+z= or ∅(null)

Explanation:it can't be solved no variable numbers.