Question

Solve the following system of linear equation x+5y=13 x-4y=-5

Answer 1

Answer:

subtract EQ 2 from 1

5y+4y=18

9y=18

y=2

substituting y in EQ 1 x+10=13

x=3

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Answer 2

Answer:

x + 5y = 13 -----> 1

x - 4y = - 5 -----> 2

solving 1 & 2 by elimination method;

x +5 y= 13

x - 4y = - 5

- + +

-------------

9y = 18

y = 18/9

y = 2

substitute the value of y = 2 in equation 1

x + 5y = 13

x + 5(2) = 13

x + 10 = 13

x = 13 - 10

x = 3

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