solve the following system of linear equation x/a + y /b = a + b, x/a2 + y / b2 = 2
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Given, x / a + y / b= a + b ............. i
x / a² + y / b²= 2.................ii
=> y/b = a+b - x/a
=> x/a² + y/b× 1/b =2
=> x/a² + a+b - x/ab =2 putting i
=> x [ b- a ] /a²b = [b- a] b
=> x= a²
=> So x= a²
using ii we get
b=y²
So x=a² and y=b² Answer.
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