Question

Solve the following system of linear equations

4x-3y=8, x-2y = -3​

Answer 1

Answer:

x = 4

y = 4

Step-by-step explanation:

$4x-3y = 8\\x-2y=-3$

Multiply 4 in x-2y=-3

$4x - 8y = -12$

Subtract

5y = 20

y=4

4x-3(4)=8

4x = 8+12

4x = 20

x=4