Solve the following system of linear equations
ax + by - a + b = 0 and bx - ay - a - b = 0. The value of x and y are
Answer with Explaination
Answers
Answered by
0
Solve for x and y:
ax+by−a+b=0,bx−ay−a−b=0.
Solution
ax+by−a+b=0
x=
a
a−b−by
bx−ay−a−b=0
b(
a
a−b−by
)−ay=a+b
ab−b
2
−b
2
y−a
2
y=(a+b)a
−(a
2
+b
2
)y=a
2
+ab+b
2
−ab
y=
−(a
2
+b
2
)
a
2
+b
2
=−1
x=
a
a−b+b
=1
So x=1 & y=−1.
Answered by
1
Answer:
ax + by = a-b
Multiplying by b we get :
⇒ abx + b²y = ab - b²....1
bx - ay = a+b
Multiplying by a we get
⇒ abx - a²y = a² + ab ....2
Subtracting 1 and 2
y(a²+b²)= -b²-a²
⇒ y=1
ax + b = a-b
⇒ ax = a - 2b
⇒ x = 1 - 2b/a and y = 1
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