Question

solve the following system of linear equations by substitution meyhod x+ 2y =0, 2x -3y =14​

Answer 1

Answer:-

• $\bf{x = 4}$

• $\bf{y = -2}$

• Given:-

$x + 2y = 0\: \: \: \: \longrightarrow{\bf{eqn.1}}$

$2x - 3y = 14 \: \: \: \: \longrightarrow{\bf{eqn.2}}$

• To Find:-

Value of:

$x =\bf{?}$

$y =\bf{?}$

• Method:-

$Substitution \: Method$

• Solution:-

$x + 2y = 0$

→ x = -2y

• Substituting this value of $\bf{x}$ in $\bf{eqn.2}$:-

We have,

→ 2(-2y) - 3y = 14

→ - 4y - 3y = 14

→ - 7y = 14

→ $y = - \dfrac{14}{7}$

→ $\bf{y = -2}$

• Substituting $\bf{y = -2}$ in $\bf{eqn.1}$:-

We have,

→ x + 2(-2) = 0

→ x - 4 = 0

→ $\bf{x = 4}$

$\large\therefore$Therefore,

• $\bf{x = 4}$

• $\bf{y = -2}$

Answer 2

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