Question

Solve the following system of linear equations by substitution method:

Q.I 2x-3y=13, 7x-2y-20

Q.2 2x+3y=7, 3x-y = 5

Q.3 -6x+3y-2=0, -5x+6y-9 = 0

Q.4 x-=3, =

Qs -=-2, +=

Q.6 3x+y+S=0, 2x+5y=1

Q.7 3x+5y-12-0, X-3y+10=0

Q. 8 7x+11y-1=0, 8x+13y=2

Q. 9 2x+y-35-0, 3x+4y-65-0​

Answer 1

Answer:

Q.1===

Step-by-step explanation:

4X-6X==26

21X-6X=60

-. +. -

--------------.

-17X=======34.

X====-2.