Solve the following system of linear equations for x and y :
ax +by = 2ab , bx +ay = a2+b2
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ax + by =2ab ..(1)
bx + ay = a²+b² ...(2)
multiply by b in (1) and a in (2)
we get ,
abx+b²y=2ab²
abx+a²y=a³+ab²
subtract (1)-(2),
Y(-a²+b²)=2ab²-a³-ab²
y(-a²+b²)=ab²-a³
y= (ab²-a³)/(-a²+b²)
y= a(b²-a²)/(b²-a²)
y=a
put value in (1),
ax+b[a]=2ab
ax=2ab-ab
ax= ab
x=ba/a
x=b
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